Find g(t) Given Wronskian and f(t)=e2t

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In summary, the Wronskian W of functions f and g is 3e4t, where f(t)=e2t. The equation g'(t)-2g(t)=3e2t is satisfied by g(t), which can be solved by using the integrating factor of e^(∫-2 dt).
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If the Wronskian W of f and g is 3e4t, and if f(t)=e2t, find g(t).

Here's the work:
e2tg'(t)-(e2t)'g(t)=3e4t
e2tg'(t)-2e2tg(t)=3e4t
g'(t)-2g(t)=3e2t
p=-2
e^integral of p=e-2t
g(t)=?
 
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I think you should leave the posting template, it's listed in the rules of the forum.

But anyways, it looks like you've shown that g(t) satisfies a linear differential equation. It also looks like you've listed an integrating factor of e^(∫-2 dt).

So, you're pretty much done. Do you know how to apply an integrating factor to solve a linear differential equation?
 
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Thanks, I've already solved it.
 

1. What is a Wronskian?

A Wronskian is a mathematical tool used to determine the linear independence of a set of functions. It is represented by the symbol W and is calculated by taking the determinant of a matrix formed by the functions and their derivatives.

2. How does the Wronskian relate to finding g(t)?

The Wronskian can be used to find the general solution, or g(t), of a differential equation when combined with an initial condition. It helps determine the coefficients in the general solution by showing the linear independence of the functions.

3. What is the significance of f(t)=e2t in this problem?

The function f(t)=e2t is important because it is one of the functions used to form the Wronskian. It is also the function given in the initial condition, which is needed to find the general solution g(t).

4. Can the Wronskian be used to find g(t) for any differential equation?

No, the Wronskian can only be used to find g(t) for linear differential equations. It cannot be used for nonlinear equations or equations with variable coefficients.

5. Are there any limitations to using the Wronskian method?

Yes, the Wronskian method can only be used when the functions in the Wronskian are continuous and differentiable on the interval of interest. It also requires the functions to be linearly independent, which may not always be the case.

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