The balanced chemical equation shows that 2 moles of potassium chlorate (KClO3) decompose to produce 2 moles of potassium chloride (KCl) and 3 moles of oxygen (O2). To find the grams of potassium chloride produced from 25 g of potassium chlorate, the calculation involves converting grams of KClO3 to moles, then using the stoichiometric ratio to find moles of KCl produced, and finally converting back to grams. The correct calculation yields approximately 15.2 g of KCl, confirming the final result is accurate despite missing a crucial stoichiometric conversion factor. The stoichiometry indicates that 2 moles of KCl are produced for every 2 moles of KClO3 decomposed, which simplifies to a 1:1 ratio.
