- #1
jesuslovesu
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(from rest)
I need to find how far a particle travels in 9 seconds
The only given is acceleration but I can find the antiderivative for velocity and position.a = 1 + 3 sqrt(t) mph/sec
v = t + 2t^(3/2) + vo mph
s = 1/2t^2 + 4/5*t^(5/2) + vo*t + so miles
9sec == .0025 hour
[tex]
\int_0 ^{0.0025} |v(t)|dt
[/tex]
When I take the integral of velocity to find distance traveled, I don't get the correct answer. (should be 344 feet) I would assume that I'm doing something wrong with the units but I can't figure it out.
I need to find how far a particle travels in 9 seconds
The only given is acceleration but I can find the antiderivative for velocity and position.a = 1 + 3 sqrt(t) mph/sec
v = t + 2t^(3/2) + vo mph
s = 1/2t^2 + 4/5*t^(5/2) + vo*t + so miles
9sec == .0025 hour
[tex]
\int_0 ^{0.0025} |v(t)|dt
[/tex]
When I take the integral of velocity to find distance traveled, I don't get the correct answer. (should be 344 feet) I would assume that I'm doing something wrong with the units but I can't figure it out.
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