Find mass of a rope pulled by a force

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The discussion revolves around calculating the mass of a rope being pulled by a force at a 30° angle with the vertical. The force balance equations derived are F sin30° = 20 and F cos30° = Mg, leading to a mass calculation of M = 2√3 Kg, which approximates to 3.5 Kg. The original answer key incorrectly lists the answer as option 4, but it is clarified that the correct option is actually 3. The calculations and reasoning presented are confirmed to be accurate. The thread concludes with an acknowledgment of the error in the answer key.
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Homework Statement


rope.jpg


Homework Equations

The Attempt at a Solution



The force F exerted by the wall on the left end of the rope will make an angle 30° with the vertical . If we do the force balance ,

F sin30° = 20
Fcos30° = Mg

This gives M = 2√3 Kg . This gives 3.5 Kg . But answer given is option 4) . What is the mistake ?

Edit : There is a mistake in the answer key . Correct option is 3) .
 

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Your force balance is correct, as is your final result.
 
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