Find max E of a photon in Compton Collision

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SUMMARY

The discussion centers on calculating the maximum energy of an x-ray photon that can impart 50 keV to an electron during a Compton collision. The relevant equations include the Compton wavelength shift formula, ∆λ=h/mc(1-cos(theta)), and the energy-frequency relationship, E=hf. The user initially calculated a change in wavelength (∆λ) of 2.43 x 10^-12 m for a scattering angle of 90 degrees, leading to an incorrect energy change (∆E) of 510,551 eV, which exceeds the target energy of 50 keV. The user seeks clarification on their approach and acknowledges a potential misunderstanding in manipulating the equations.

PREREQUISITES
  • Understanding of Compton scattering principles
  • Familiarity with the Compton wavelength shift equation
  • Knowledge of the relationship between energy and frequency (E=hf)
  • Basic concepts of photon energy calculations
NEXT STEPS
  • Review the derivation and application of the Compton wavelength shift formula
  • Study the implications of scattering angles on energy transfer in Compton collisions
  • Learn about the conservation of energy and momentum in particle collisions
  • Explore practical examples of photon energy calculations in high-energy physics
USEFUL FOR

Physics students, educators, and professionals interested in high-energy particle interactions, particularly those studying Compton scattering and photon energy calculations.

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Homework Statement



Find the energy of an x-ray photon that can impart a max energy of 50keV to an electron by compton collision

Homework Equations



∆λ=h/mc(1-cos(theta)) where m = mass of electron
E=hf
(to be honest, not entierly sure if these are all you need, or if you need them... sorry :( )

The Attempt at a Solution



∆λ=2.43*10^-12 (set theta to 90 because i am dealing with a maximum)

corresponding change in f = c/2.43*10^-12 from above
and since E=hf
∆E=510551 eV which is unfortunately, larger than the E delivered to the electron... so CLEARLY I've stuffed up... I was planning on being able to say that the energy was 50keV + ∆E so i guess I'm on the wrong track... very wrong... any hints would be very greatly appreciated :!)
 
Physics news on Phys.org
You are changing an equation like f-f'=c/lambda-c/lambda' into f-f'=c/(lambda-lambda'). This is WRONG! Right?
 

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