Find min. speed and direction of velocity, given parametric eqns

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SUMMARY

The discussion focuses on determining the minimum speed and direction of velocity for a hockey puck sliding along the ice, described by the parametric equations r(t) = (cos(4πt) + 5√2t, sin(4πt) + 5√2t). The puck has a radius of 1 and moves at a speed of 10 in the direction of the vector (1,1), while spinning counterclockwise at 2 revolutions per unit time. The velocity is calculated as v(t) = (-4πsin(4πt) + 5√2, 4πcos(4πt) + 5√2), with the acceleration derived as v’(t) = (-16π²cos(4πt), -16π²sin(4πt)). The extremum of speed occurs when the rotational speed aligns with the linear movement.

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Homework Statement


A hockey puck of radius 1 slides along the ice at a speed 10 in the direction of the vector (1,1). As it slides, it spins in a counterclockwise direction at 2 revolutions per unit time. At time t = 0, the puck’s center is at the origin (0,0).

Find the parametric equations for the trajectory of the point P on the edge of the puck initially at (1,0).

radius = R = 1
frequency = f = 2
angular frequency = w = 2πf = 4π
θ = wt

Thus, I found r(t) = (cos4πt + 5sqrt2t, sin4πt + 5sqrt2t)

Now that I have the equation of the trajectory, how do I find the minimum speed of the point P, and the direction of the velocity at the corresponding time?

Homework Equations



The Attempt at a Solution


Velocity: v(t) = (-4πsin4πt + 5sqrt2, 4πcos4πt + 5sqrt2)
v’(t) = (-16π2cos4πt, -16π2sin4πt) = 0
 
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The puck is rotating so its acceleration is never zero; however it is easy to guess that the speed of P is extremized when the speed due to rotation is to the same direction as the linear movement.
 

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