Find Norm on R2 with ||(0,1)||=1=||(1,0)|| & ||(1,1)||=0.000001

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Homework Statement


find a norm on R2 for which||(0,1)||=1=||(1,0)|| but ||(1,1)||=0.000001




Homework Equations


hints: ||(a,b)|| = A |a+b|+B|a-b


The Attempt at a Solution


by the hints i have A+B=1 and 2A=0.000001
then solved the equations system i get A=0.0000005 B=1-A=0.9999995 then ||(a,b)|| = 0.000001|a+b|+0.9999995 |a-b|

is it the answers?
 
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cummings12332 said:

Homework Statement


find a norm on R2 for which||(0,1)||=1=||(1,0)|| but ||(1,1)||=0.000001




Homework Equations


hints: ||(a,b)|| = A |a+b|+B|a-b


The Attempt at a Solution


by the hints i have A+B=1 and 2A=0.000001
then solved the equations system i get A=0.0000005 B=1-A=0.9999995 then ||(a,b)|| = 0.000001|a+b|+0.9999995 |a-b|

is it the answers?
Yes, these values satisfy the given conditions.
 
Another solution would be to use a p-norm:
||(a,b)|| = (a^p + b^p)^{1/p}
with p \geq 1. This will satisfy ||(1,0)|| = ||(0,1)|| = 1 for any p, so all you have to do is solve for the p which gives the desired result for ||(1,1)||.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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