Find number of turns in the solenoid

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To find the number of turns in a solenoid given the speed of an electron, diameter of its circular path, length of the solenoid, and current, the relevant equations are QvB = v²m/r and B = μNI/l. After substituting B into the first equation and solving for N, a result of 0.121 turns is obtained, which is not valid since the number of turns must be at least one. Users suggest posting calculations to identify any errors, and it is recommended to round up to N=1 if necessary. The problem specifies that the electron follows a circular path within the solenoid, which may affect the calculations.
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Homework Statement


I have the following information about the problem.

i have the speed of an electron = v
the diameter of a circular path = d
the length of a solenoid = x
the current that the solenoid carried = I

I need to find the number of turns in the solenoid.

Homework Equations



i used the following equations
QvB=v2m/r

B=\muNI/l

The Attempt at a Solution



then i put "B" in the first equation and i solve for N. Is that correct?
 
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Yes, do that.
 


the only weird thing is that i get a number like

.121

and it is not a turn .121? or it can be a valid answer?
 


jackxxny said:
the only weird thing is that i get a number like

.121

and it is not a turn .121? or it can be a valid answer?

no, you can't really get less than one. Post the numbers and your working and we'll see if you went wrong anywhere.
 


v=1570 m/s
d = 1.57 cm
x = 35 cm
I = 2.61 A
what I did is :
N=(vmx)/(rQI*4*pi*10^-7)
 


I get the same answer as you, so I guess you'll need to put what you get and round up and put N=1
 


the problem really states...

...that the electron follows a circular path of diameter 1.57 cm near the center of an evacuated solenoid of length 35 cm .

does that changes anything?
 
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