- #1

nycmathdad

- 74

- 0

The words "how many ways" reminds of probability. I just don't recall if this is a combination or a permutation.

I will take a guess and say this is a combination problem.

The set up is 5C2.

You say?

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- MHB
- Thread starter nycmathdad
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- #1

nycmathdad

- 74

- 0

The words "how many ways" reminds of probability. I just don't recall if this is a combination or a permutation.

I will take a guess and say this is a combination problem.

The set up is 5C2.

You say?

- #2

jonah1

- 108

- 0

I say stop guessing.At a ...

I will take a guess and say this is a combination problem.

The set up is 5C2.

You say?

You have a textbook.

Look it up laddie.

- #3

HOI

- 923

- 2

There are a total of 5(4)= 20 ways that could be done.

(Since order, which dog is "best in show" and which is "honorable mention", is relevant, this is a "permutation" problem but, as I say, that is really not important.)

- #4

nycmathdad

- 74

- 0

There are a total of 5(4)= 20 ways that could be done.

(Since order, which dog is "best in show" and which is "honorable mention", is relevant, this is a "permutation" problem but, as I say, that is really not important.)

Are you saying that that 5C2 should be 5P2?

Let me see.

5P2 = 5!/(5 - 2)!

5P2 = 120/(3)!

5P2 = 120/6

5P2 = 20 ways.

When it comes to combination versus permutation, in terms of combination order does matter. Order does not matter in terms of permutation. Can you explain why that is the case using a simple math example for both cases?

- #5

jonah1

- 108

- 0

There you go again asking volunteer helpers to post a war and peace explanation for something that you could just read from your textbook. Read your book. Reading is good for you....

When it comes to combination versus permutation, in terms of combination order does matter. Order does not matter in terms of permutation. Can you explain why that is the case using a simple math example for both cases?

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