Calculate R1 and R2 given equivalent resistance

In summary: Doing so gives me the following two equations:1. The expression for the gate potential (voltage divider)2. The expression for RinThis is very similar to the textbook solution, but I think my approach is a little more direct and simplified.
  • #1
SuperCat
26
1
Note: I have come up with a solution myself, but I am trying to understand a different approach to the problem. My textbook solves it in a different manner, and I am having trouble following along.

Homework Statement


The last part of the problem "determine R1 and R2 such that Rin = 200k". I am having trouble understanding the solution for it. Note the graph for the problem is on the left.
5c6db0e3b46eafad9b26f130c72d4fdc.png


Homework Equations


Ohm's law and KVL.

The Attempt at a Solution


Solution provided to me:
7c9f13e0ba2ff972f0f2f2521767cf3a.png

The solution for the resistance starts towards the bottom, once the gate voltage has been calculated. I do not understand why that formula is used to solve for the first resistor. To me it looks like conductance of the first resistor is being used with the Vdd to get a current. That current is being multiplied by the equivalent thevinin resistance of the two resistors. I just don't understand why that would be useful/how that would lead to calculating the resistance.
 
Last edited:
Physics news on Phys.org
  • #2
I have just come up with a solution myself. I took a very different approach but received the same answer.
Here is my approach:
9b4f352da704a20f4d22e538156ac405.png


I receive the correct answer, and I found this to be more straightforward. But I would appreciate if someone could explain to me how the textbook solution goes along.
 
  • #3
Write two equations that involve R1 and R2:

1. The expression for the gate potential (voltage divider)
2. The expression for Rin

Look for commonalities in the two expressions that you can exploit.
 
  • #4
gneill said:
Write two equations that involve R1 and R2:

1. The expression for the gate potential (voltage divider)
2. The expression for Rin

Look for commonalities in the two expressions that you can exploit.
Isn't that similar to what I have in the post above? I think my textbook does it with a current divider. Which gives me the impression that they had decided to assume there an AC signal, and decide to do small signal analysis.
 
  • #5
SuperCat said:
Isn't that similar to what I have in the post above?
Yup. But then it's bound to be similar since there's not much leeway as to what are the "givens".

What I picked out and exploited was the fact that the term ##\frac{R_2}{R_1 + R_2}## occurs in both equations, and its occurrence in the voltage divider equation can be replaced with its value from the input resistance equation.
 

1. What is equivalent resistance?

Equivalent resistance is the total resistance measured in an electrical circuit when multiple resistors are present. It is calculated by combining the individual resistances using Ohm's law.

2. How do I calculate R1 and R2 given equivalent resistance?

R1 and R2 can be calculated using the formula 1/Rt = 1/R1 + 1/R2, where Rt is the equivalent resistance and R1 and R2 are the individual resistances. Rearranging the formula, we get R1 = (Rt * R2)/(R2 - Rt) and R2 = (Rt * R1)/(R1 - Rt).

3. What units are used for resistance?

The unit for resistance is ohms (Ω).

4. Can the equivalent resistance ever be lower than the smallest individual resistance?

No, the equivalent resistance can never be lower than the smallest individual resistance. It can only be equal to or greater than the smallest resistance.

5. What factors can affect the calculated R1 and R2 values?

The calculated R1 and R2 values can be affected by the precision of the measurements, the accuracy of the equipment used, and any external factors such as temperature or humidity that may impact the resistance of the materials used.

Similar threads

  • Engineering and Comp Sci Homework Help
Replies
5
Views
3K
  • Engineering and Comp Sci Homework Help
Replies
4
Views
1K
  • Engineering and Comp Sci Homework Help
Replies
2
Views
2K
  • Engineering and Comp Sci Homework Help
Replies
18
Views
2K
  • Engineering and Comp Sci Homework Help
Replies
11
Views
5K
  • Engineering and Comp Sci Homework Help
Replies
8
Views
1K
  • Engineering and Comp Sci Homework Help
Replies
8
Views
1K
  • Engineering and Comp Sci Homework Help
Replies
1
Views
1K
  • Engineering and Comp Sci Homework Help
Replies
6
Views
1K
  • Engineering and Comp Sci Homework Help
Replies
34
Views
4K
Back
Top