Find Shear Stress in Shaft Design | Modulus of Rigidity 80kN/mm2

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SUMMARY

The discussion centers on calculating shear stress in shaft design, specifically under the condition that the angle of twist must not exceed 1° over a length equal to 20 diameters. Given a modulus of rigidity of 80 kN/mm², participants explore the implications for stress in the material. The consensus indicates that using the formula τ = GθL/J, where τ is shear stress, G is the modulus of rigidity, θ is the angle of twist in radians, L is the length of the shaft, and J is the polar moment of inertia, is essential for deriving the required shear stress.

PREREQUISITES
  • Understanding of shear stress and its significance in mechanical design
  • Familiarity with modulus of rigidity and its application in material science
  • Knowledge of polar moment of inertia and its calculation for circular shafts
  • Basic grasp of angular displacement and its conversion from degrees to radians
NEXT STEPS
  • Study the derivation and application of the torsion formula in shaft design
  • Learn about calculating the polar moment of inertia for various shaft geometries
  • Explore the effects of different materials on shear stress and modulus of rigidity
  • Investigate advanced topics in torsional rigidity and its implications in engineering design
USEFUL FOR

Mechanical engineers, design engineers, and students studying materials science or mechanical design principles will benefit from this discussion, particularly those focused on shaft design and torsional analysis.

loststudent123
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A rule often used in shaft design states that the angle of twist shall not exceed 1 on a length equal to 20 diameters. What stress in the material does this imply if the modulus of rigidity is equal to 80 × 103 N/mm2 ?
was wondering if anybody had an insight on how to do this ?

have tried a few ways but keep being left with 2 unknowns
 
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