Find Sin(P + Q) from 2 equations

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AI Thread Summary
In triangle PQR, the equations 3SinP + 4CosQ = 6 and 4SinQ + 3CosP = 1 are provided to find sin(P + Q) and the measure of angle R. The solution for sin(P + Q) is given as 1/2, while angle R measures pi/6 radians. To solve the equations, it is suggested to square the expressions for sin P and cos P, then add them and apply the identity sin²x + cos²x = 1 to simplify. This approach aims to isolate and determine the values of angles P and Q. The discussion emphasizes the need for algebraic manipulation to reach the solution.
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Homework Statement


In triangle PQR, 3SinP + 4CosQ = 6 and 4SinQ + 3CosP = 1. a) Find sin(P + Q). b) Determine the measure of angle R, in radians. The answer given for part a) is 1/2 and part b) pi/6

Homework Equations


Sin (A+B) = SinACosB + CosASinB

The Attempt at a Solution


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Thats what I've tried and I simply don't understand how to solve it...
 
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Try squaring your expressions for sin P and cos P and adding them together and simplify the resulting equation using the identity sin2 x + cos2 x = 1. I think that'll let you eventually solve for Q. Once you have Q, you can solve for P.
 
I picked up this problem from the Schaum's series book titled "College Mathematics" by Ayres/Schmidt. It is a solved problem in the book. But what surprised me was that the solution to this problem was given in one line without any explanation. I could, therefore, not understand how the given one-line solution was reached. The one-line solution in the book says: The equation is ##x \cos{\omega} +y \sin{\omega} - 5 = 0##, ##\omega## being the parameter. From my side, the only thing I could...

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