Find sound wavelength from a vibrating string

AI Thread Summary
To find the wavelength of the sound wave from a vibrating piano string, the fundamental frequency of the string must first be calculated using the formula f_1 = (1/2L)√(T/μ), where L is the length, T is the tension, and μ is the mass density. The speed of the wave on the string can be determined using v = √(T/μ), and the relationship between frequency and wavelength is given by v = fλ. The allowed wavelengths can be expressed as λ = 2L/n, where n represents the mode of oscillation. The discussion clarifies that the linear mass density is denoted as μ, confirming its relevance to the problem. Understanding these relationships allows for the calculation of the sound wavelength heard by the listener.
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Homework Statement


Sound Wavelength From String
During a concert a pianist hits a key that sets up a standing wave in a piano string that is vibrating in its fundamental mode. The string is 0.5 m long, has a mass density of 0.002 kg/m and is held under a tension of 120 N. What is the wavelength of the sound wave heard by the listener? The speed of sound in air is 343 m/s.
v (sound) = 343 m/s
L (length) = 0.5 m
d (mass density) = 0.002 kg/m
T (tension) = 120 N
λ (wavelength) = unknown

Homework Equations


v = f*λ = ω/k

f = frequency
k = spring constant
ω = angular frequency

v = √(T/(m/L))

T = force of tension
m = mass
L = length

The Attempt at a Solution


At first I attempted a solution using the second equation provided, however I am not quite sure what I would be solving for since the speed of sound in air is provided. Using the second equation I find the speed of the wave itself, but I am not sure how to apply the two speeds to finding the wavelength of the sound wave? Please help me with this problem!
 
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First find the frequency of vibration of the string.
 
The fundametnal frequency is f_1=\frac{1}{2L}\sqrt{\frac{T}{\mu}} They're giving you the info to find the frequency, they're giving you the velocity, so use that to find wavelength.
 
Just to add:
The frequency of vibration, f = \frac{v}{λ} = \frac{nv}{2L}. The allowed wavelengths are: λ = \frac{2L}{n}, where n is the mode of oscillation.

Note also, in your listing of equations, you write that v = \frac{ω}{k} and say that k is the spring constant. This is not the case here, instead it is defined as the wavenumber, where k = \frac{2π}{λ}. Substitution of this and ω = 2πf gives back v = fλ.
 
Wow! Thank you so much. That made a lot more sense to me than when I first attempted the problem. Thanks :)
 
Just to double check with you, the μ in this case is referring to the density given correct?
 
yes, μ is the linear mass density, kg/m, which is what you're given as "d" actually.
 
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