rgalvan2
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Find an equation for the line tangent to the given path at the indicated value for the parameter.
x(t)=4costi-3sintj+5tk, t=[tex]\pi[/tex]/3
So what I did here was take x'(t) and then plugged in [tex]\pi[/tex]/3 after that to get an equation containing i, j, and k.
x'(t)= -4sinti-3costj+5k
x'([tex]\pi[/tex]/3)=-4[tex]\sqrt{3}[/tex]/2i-3/2j+5k
Am I doing this right? Calc III is confusing me so much. Any help would be appreciated. This is due Thursday. Thanks!
x(t)=4costi-3sintj+5tk, t=[tex]\pi[/tex]/3
So what I did here was take x'(t) and then plugged in [tex]\pi[/tex]/3 after that to get an equation containing i, j, and k.
x'(t)= -4sinti-3costj+5k
x'([tex]\pi[/tex]/3)=-4[tex]\sqrt{3}[/tex]/2i-3/2j+5k
Am I doing this right? Calc III is confusing me so much. Any help would be appreciated. This is due Thursday. Thanks!