Find the average shear stress at each pin

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SUMMARY

The discussion focuses on calculating the average shear stress at each pin in a structural analysis problem. The correct shear stress at each pin is established as 324 MPa, with the area calculated to be 508.94 mm². Initial calculations for forces at points A and BC were incorrect, with the corrected force at BC being 165 kN directed up and to the right, and the components at A being A_x = 142.89 kN to the right and A_y = 82.5 kN upward. The confusion arises from understanding why all pins yield the same shear stress result despite differing force components.

PREREQUISITES
  • Understanding of shear stress calculations using the formula τ = V/A
  • Familiarity with structural analysis concepts, particularly pin reactions
  • Knowledge of force decomposition into x and y components
  • Ability to interpret and analyze structural diagrams
NEXT STEPS
  • Review the principles of shear stress in structural engineering
  • Learn about calculating reaction forces in pin-connected structures
  • Study the effects of varying load conditions on shear stress distribution
  • Explore advanced topics in finite element analysis for complex structures
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Engineering students, structural analysts, and professionals involved in mechanical and civil engineering who are focused on understanding shear stress in pin connections.

ptguard1
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Homework Statement



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Homework Equations



tao = V/A

The Attempt at a Solution



I went ahead and solved the force at BC and the x and y components at A, but I feel as though my solutions are incorrect. At BC I have F = 825 kN (up and to the left), A_x = 714.5 kN positive, A_y = 247.5 kN downward. I don't know how to solve the pins from here. The correct answer at each pin is 324MPa. I found the area to be 508.94mm^2 but am unable to find what force is pulling on each pin.
 

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ptguard1: Your area is correct. Your reaction forces are currently incorrect. If you want to show your work, someone might check your math.
 
I recalculated my solutions and found my mistake. F at BC = 165 kN (up and to the right), A_x = 142.89 kN to the right, A_y = 82.5 kN up. The issue I'm having is solving for the shear stress in the pins. I don't understand why all of the pins would have the same result.

For the pin at A, I interpret it as shown in the attached image

I used the equation A_x/Area, but i know that I need the force to be 165kN
 

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Last edited:

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