Find the coordinates of a point where a line intersects the y-axis.

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Homework Help Overview

The problem involves finding the coordinates of a point where a given line intersects the y-axis in a three-dimensional space. The line is described by a parametric equation.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the concept of y-intercepts in 3D and question how to determine the intersection point. There are attempts to clarify the conditions under which the x and z coordinates must be zero to find the intersection.

Discussion Status

The discussion is active, with participants exploring different interpretations of the problem and checking assumptions about the coordinates. Some guidance has been offered regarding the conditions needed to find the intersection point.

Contextual Notes

There is some confusion regarding the algebra involved in determining the coordinates when substituting values into the parametric equation. Participants are working through the implications of their calculations and the definitions involved.

vparikh
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Homework Statement



The following equation describes a straight line:
⟨x, y, z⟩ = ⟨−1, 0, −2⟩ + t⟨1, 2, 2⟩
Find the coordinates of the point where this line intersects the y-axis.

Homework Equations



Equation of a Line: r = ro + tv

The Attempt at a Solution



I'm not really sure how y-intercepts work in 3d and I'm having trouble even attempting a solution. My guess was the ro point <-1,0,-2> because the y coordinate is zero but I don't think that it would be that easy. Also, this is my first time posting a question on the Physics Forum site so please go easy on me if I messed anything up :)
 
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vparikh said:

Homework Statement



The following equation describes a straight line:
⟨x, y, z⟩ = ⟨−1, 0, −2⟩ + t⟨1, 2, 2⟩
Find the coordinates of the point where this line intersects the y-axis.

Homework Equations



Equation of a Line: r = ro + tv

The Attempt at a Solution



I'm not really sure how y-intercepts work in 3d and I'm having trouble even attempting a solution. My guess was the ro point <-1,0,-2> because the y coordinate is zero but I don't think that it would be that easy. Also, this is my first time posting a question on the Physics Forum site so please go easy on me if I messed anything up :)

It's almost that easy. <-1,0,-2> is in the x-z plane, it isn't on the y-axis. A point on the y-axis looks like <0,y,0>.
 
So then it has to be the point when the x and z coordinates are zero?
 
vparikh said:
So then it has to be the point when the x and z coordinates are zero?

Yes. What is it?
 
Well the equation multiplied out would be

<t-1,2t,2t-2>

so to make the x and z zero, x has to be 1 and y has to be 1.

So would <1,1,1> be a point that this line intersects the y axis?
 
vparikh said:
Well the equation multiplied out would be

<t-1,2t,2t-2>

so to make the x and z zero, x has to be 1 and y has to be 1.

So would <1,1,1> be a point that this line intersects the y axis?

Not quite sure what you are thinking there. I would say to put x=0 you should pick t=1.
 
Okay, so where t=1 the coordinates are <0,0,0> and thus intersect the y-axis at that point?
 
Wait, no it would be <0,2,0>
 
vparikh said:
Okay, so where t=1 the coordinates are <0,0,0> and thus intersect the y-axis at that point?

?Can you explain how putting t=1 into <t-1,2t,2t-2> gives you <0,0,0>?
 
  • #10
Dick said:
?Can you explain how putting t=1 into <t-1,2t,2t-2> gives you <0,0,0>?

Sorry, bad algebra. <0,2,0>
 
  • #11
vparikh said:
Sorry, bad algebra.

Ok. Yes, it's <0,2,0>.
 
  • #12
Dick said:
Ok. Yes, it's <0,2,0>.

Thanks for the help, I really appreciate it!
 

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