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## Homework Statement

Find the critical numbers of the function

y=√(1-x^2)

## The Attempt at a Solution

y'=-x/√(1-x^2 )=0

-x/√(1-x^2 )=0

Here, I stuck. If I continue with this equation, my answers are x1=0 and x2 is less than 1.

But if I try to get rid of the root in order to find the critical points by doubling the both sides of equation, my answer is x1=0, x2 not equal to 1.

These are quite different answers. Please help me out with the problem.