1. Limited time only! Sign up for a free 30min personal tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Find the critical numbers of the function

  1. Jul 6, 2010 #1
    1. The problem statement, all variables and given/known data

    Find the critical numbers of the function

    3. The attempt at a solution

    y'=-x/√(1-x^2 )=0
    -x/√(1-x^2 )=0

    Here, I stuck. If I continue with this equation, my answers are x1=0 and x2 is less than 1.
    But if I try to get rid of the root in order to find the critical points by doubling the both sides of equation, my answer is x1=0, x2 not equal to 1.

    These are quite different answers. Please help me out with the problem.
  2. jcsd
  3. Jul 6, 2010 #2


    Staff: Mentor

    Critical numbers occur at places where the derivative is 0, or at places in the domain of the function where the derivative is undefined, or at endpoints of the domain.

    Seems to me that there are three critical numbers.
  4. Jul 6, 2010 #3
    Do you mean 0, 1, and -1?


    1-x^2=0 =>x=+-1

    Is that what you mean?
  5. Jul 7, 2010 #4


    Staff: Mentor

    Yes, that's what I mean.
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook