A network consists of a combination of parallel and series connections. What is the equivalent resistance of the network? (Hint: Use the series and parallel resistance formulas).
The network looks like this:
When a circuit is in series, R = R1 + R2 + R3...
When a circuit is in parallel, R = 1/R1 + 1/R2 + 1/R3...
The Attempt at a Solution
First, c and b are in series, so I just add them up. 5 + 3 = 8.
Now, a, d, and this new resistor of value 8 are in series. So add them up again.
8 + 4 + 1 = 13.
Did I do that correctly?
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