- #1
notorious_lx
- 5
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1. Ok, so the question is.. Find the exact volume of the solid bounded above by the surface [itex]z=e^{-x^2-y^2}[/itex], below by the xy-plane, and on the side by [itex]x^2+y^2=1[/itex].
2. Alright. So, I know that I can use a double integral to find the volume, and switching to polar coordinates would be simpler.[itex] z=e^{-r^2}[/itex] and [itex]r^2 =1[/itex], therefore [itex]z=e^{-1}[/itex].
3. I'm not sure how to calculate the double integral. I know volume would be the double integral of the top surface minus the bottom surface, but do i need to split the surface into two separate double integrals and add them together? This should be easy but I can't seem to figure this out.
2. Alright. So, I know that I can use a double integral to find the volume, and switching to polar coordinates would be simpler.[itex] z=e^{-r^2}[/itex] and [itex]r^2 =1[/itex], therefore [itex]z=e^{-1}[/itex].
3. I'm not sure how to calculate the double integral. I know volume would be the double integral of the top surface minus the bottom surface, but do i need to split the surface into two separate double integrals and add them together? This should be easy but I can't seem to figure this out.
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