Find the force acting on the charge at the origin

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SUMMARY

The discussion focuses on calculating the force acting on a charge of 1.6 nC located at the origin due to two other charges: 2.6 nC at (0.55, 0) and -2.1 nC at (0, 1.15). The correct formula used is F = kQQ/r², where k = 9 x 10^9 N m²/C². The x-component of the force (Fx) was initially miscalculated due to incorrect distance usage, while the y-component (Fy) was also under scrutiny for sign determination. The final answers should reflect the correct distances and signs based on the charge interactions.

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Homework Statement


Three charges are fixed in the x-y plane as follows: 1.6nC at the origin (0, 0); 2.6nC at (0.55 , 0); –2.1 nC at (0, 1.15 ).

Find the force acting on the charge at the origin.
Express your answers using two significant figures. Enter the x and y components of the force separated by a comma.

Homework Equations


F=kQQ/r^2


The Attempt at a Solution


Fx=(2.6E-9*1.6E-9*9E-9)/1.15^2=1.24*10^-25N
Fy=(2.1E-9*1.6E-9*9E-9)/0.55^2=2.29*10^-26N
This is wrong but i can't see why??
 
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For Fx r is 0.55 m not 1.15 m. And k = 9*10^9
 
thanks rl.bhat I have the right answers now. I just don't know which one would be negative, I am thinking Fy? thanks
 

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