Find the force between two wires

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Homework Statement


Two rectilinear wires with length 100 m have the intensity 2 A. The wires in are perpendicular directions with distance 5 meters from each-other. Find the force they interact.

Homework Equations


F=(I1*I2*μ0*l)/(2*pi*d)

The Attempt at a Solution


F=(2*2*4*pi*10^-7*1)/(2*3.14*5)=1.6*10^-7
The solution in my book is 0 N.
 
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BvU said:
Check the direction of the magnetic fields and the direction of the currents...
I think the currents are perpendicular with each other and so are the vectors of magnetic induction.
 
zade70 said:
I think the currents are perpendicular with each other and so are the vectors of magnetic induction.
Yep. So what force would that generate?
 
berkeman said:
Yep. So what force would that generate?
I can't find an argument for that.
 
zade70 said:
I can't find an argument for that.
Okay, so I'm getting the impression that you have not been exposed to the vector relationship between the current in a wire and the B-field that circulates around it, is that right? Also, have you learned how to calculate the vector Lorentz Force?
 
berkeman said:
Okay, so I'm getting the impression that you have not been exposed to the vector relationship between the current in a wire and the B-field that circulates around it, is that right? Also, have you learned how to calculate the vector Lorentz Force?
I don't know what the Lorentz Force is. I know that F=B(induction)*l(length)*I(intensity)*sin alpha. I also know that the force is perpendicular with current and induction
 
zade70 said:
I don't know what the Lorentz Force is. I know that F=B(induction)*l(length)*I(intensity)*sin alpha
Do they have any diagrams in your textbook that show a current carrying wire and the B-field circling around the wire? Do they discuss and show the "Right Hand Rule" for the direction of the B-field? I'm just trying to get a feel for how the book wants you to know how to answer this question...
 
berkeman said:
Do they have any diagrams in your textbook that show a current carrying wire and the B-field circling around the wire? Do they discuss and show the "Right Hand Rule" for the direction of the B-field? I'm just trying to get a feel for how the book wants you to know how to answer this question...
Yes. I have learned the Right Hand Rule. Actually I am doing some problems that are not from the book I'm studying and I don't know which is appropriate for me to do with the knowledge I have so far.
 
zade70 said:
Yes. I have learned the Right Hand Rule. Actually I am doing some problems that are not from the book I'm studying and I don't know which is appropriate for me to do with the knowledge I have so far.
Ah, that might explain it. Yeah, just using the force formula for parallel wires will not work for perpendicular wires.

The B-field for a current carrying wire looks like this:

http://hyperphysics.phy-astr.gsu.edu/hbase/magnetic/magcur.html#c1
magcur.gif


And the Lorentz Force is written as the cross product of two vectors: F = qv X B Where F is the force vector, v is the velocity vector of a charge, and B is the magnetic field vector. Vectors have both a Magnitude and a Direction.

The vector cross product can be simplified if you are not familiar with it, so the Lorentz force can be re-written as magnitudes only F = qvB sin(θ), where θ is the angle between the velocity vector v and the magnetic field vector B. So the result of the cross product is maximized when v and B are in the same (or opposite) direction, and it is zero when they are perpendicular.

Does that help some? You can do more reading about this at Hyperphysics or Wikipedia. :smile:

Edit -- not sure why the image is not displaying correctly, but you can click on the link to see it.
 
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