Find the force on each side of the loop

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To find the force on each side of a square loop carrying a current in a solenoid, the magnetic field inside the solenoid must be calculated using the formula B = μnI, where μ is the permeability of free space, n is the number of turns per unit length, and I is the current. Given the solenoid's specifications, the magnetic field can be determined, and the force on each side of the loop can be calculated using the formula F = I(L x B), where L is the length vector of each side of the loop. The torque acting on the loop can be found using τ = r x F, where r is the position vector from the axis of rotation to the point where the force is applied. It's important to visualize the loop's orientation relative to the magnetic field, which is uniform and perpendicular to the loop's plane. Understanding these concepts is crucial for solving the problem effectively.
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Homework Statement



A single-turn square loop of wire 2.00 cm on a side carries a counterclockwise current of .200A. The loop is inside a solenoid, with the plane of the loop perpendicular to the magentic field of the solenoid. The solenoid has 30 turns per centimeter and carries a counterclockwise current of 15.0A. Find the force on each side of the loop and the torque acting on the loop.

Homework Equations



B=unI

The Attempt at a Solution



I'm really confused about visualizing this situation, and figuring out what exactly their asking for. I guess that's my first problem.
 
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Hint: The magnetic field inside a solenoid is uniform. Just treat it as a region of space where B is constant.
 

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