Find the Fourier series for the periodic function

Click For Summary

Homework Help Overview

The discussion revolves around finding the Fourier series for the periodic function f(x) = x^2 defined on the interval (-π, π) and extended periodically. The original poster seeks to prove specific summation identities related to the Fourier series coefficients.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to derive the Fourier series and expresses uncertainty about the correctness of their findings. They also inquire about how to proceed with proving the summation identities.
  • Some participants suggest checking specific values of x to derive the required results from the Fourier series.
  • There are discussions about the notation used for summations and suggestions for clearer representations.

Discussion Status

Participants have provided feedback on the original poster's Fourier series expression, noting a correction regarding the notation. The original poster acknowledges the mistake and expresses a desire to learn more about using LaTeX for clarity in future posts. The conversation appears to be ongoing with no explicit consensus reached on the proofs.

Contextual Notes

The original poster mentions missing lectures due to illness, which may contribute to their uncertainty about the problem. There is also a focus on improving communication through LaTeX formatting in future discussions.

CricK0es
Messages
54
Reaction score
3
< Mentor Note -- thread moved to HH from the technical forums, so no HH Template is shown >[/color]

Hi all. I'm completely new to these forums so sorry if I'm doing anything wrong.

Anyway, I have this question...
Find the Fourier series for the periodic function

f(x) = x^2 (-pi < x < pi), f(x) = f(x+2pi)

By considering the particular values x = 0 and x = +/- pi prove that​

∞^Σ (n=1) 1 / n^2 = pi^2 / 6

and

∞^Σ (n=1) (-1)^n / n^2 = -pi^2 / 12

I missed a couple of lectures due to illness so I'm not entirely sure what to do with this.

But I have worked through and found the FS itself. Whether it's right I really don't know...

= pi^2 / 3 + ∞^Σ (n=1) 4/n (-1)^n Cos(nx)


Again, I'm really sorry that it's all a bit messy but I'm still getting use to everything. I would like to learn how to use LaTeX to make equations easier/clearer also. But, regardless, I would really appreciate some guidance on how to proceed through the question. Many thanks​
 
Last edited by a moderator:
Physics news on Phys.org
CricK0es said:
< Mentor Note -- thread moved to HH from the technical forums, so no HH Template is shown >

Hi all. I'm completely new to these forums so sorry if I'm doing anything wrong.

Anyway, I have this question...
Find the Fourier series for the periodic function

f(x) = x^2 (-pi < x < pi), f(x) = f(x+2pi)

By considering the particular values x = 0 and x = +/- pi prove that​

∞^Σ (n=1) 1 / n^2 = pi^2 / 6

and

∞^Σ (n=1) (-1)^n / n^2 = -pi^2 / 12

I missed a couple of lectures due to illness so I'm not entirely sure what to do with this.

But I have worked through and found the FS itself. Whether it's right I really don't know...

= pi^2 / 3 + ∞^Σ (n=1) 4/n (-1)^n Cos(nx)


Again, I'm really sorry that it's all a bit messy but I'm still getting use to everything. I would like to learn how to use LaTeX to make equations easier/clearer also. But, regardless, I would really appreciate some guidance on how to proceed through the question. Many thanks​
Your Fourier Series is correct. So you have$$
x^2 = \frac {\pi^2} 3 + \sum_{n=1}^\infty \frac{4(-1)^n}{n^2}\cos(nx)$$on the interval ##[-\pi,\pi]##. Try plugging in the two values to see if you can arrange it to get your results.
 
Last edited:
  • Like
Likes   Reactions: CricK0es
It's probably just a typo, but the Fourier series should be
$$\frac{\pi^2}{3}+\sum_{n=1}^\infty \frac{4(-1)^n}{n^2}\cos nx.$$ The ##n## in the denominator is squared.
 
  • Like
Likes   Reactions: CricK0es
vela said:
It's probably just a typo, but the Fourier series should be
$$\frac{\pi^2}{3}+\sum_{n=1}^\infty \frac{4(-1)^n}{n^2}\cos nx.$$ The ##n## in the denominator is squared.
Yes, thanks. Fixed but likely irrelevant given that the OP never returned.
 
  • Like
Likes   Reactions: epenguin
Yeah sorry guys. I thought I'd marked it as solved, and so hadn't been on the forums. I had made a mistake on the denominator but I noticed and fixed it. Thank you both
 
CricK0es said:
< Mentor Note -- thread moved to HH from the technical forums, so no HH Template is shown >

Hi all. I'm completely new to these forums so sorry if I'm doing anything wrong.

Anyway, I have this question...
Find the Fourier series for the periodic function

f(x) = x^2 (-pi < x < pi), f(x) = f(x+2pi)

By considering the particular values x = 0 and x = +/- pi prove that​

∞^Σ (n=1) 1 / n^2 = pi^2 / 6

and

∞^Σ (n=1) (-1)^n / n^2 = -pi^2 / 12

I missed a couple of lectures due to illness so I'm not entirely sure what to do with this.

But I have worked through and found the FS itself. Whether it's right I really don't know...

= pi^2 / 3 + ∞^Σ (n=1) 4/n (-1)^n Cos(nx)


Again, I'm really sorry that it's all a bit messy but I'm still getting use to everything. I would like to learn how to use LaTeX to make equations easier/clearer also. But, regardless, I would really appreciate some guidance on how to proceed through the question. Many thanks​
If you are going to use plain text, it is better to write your summations as something like sum_{n=1 ..∞} a_n or sum(a_n: n=1..∞), and you can, of course, replace the word "sum" by the symbol Σ. Constructions like your ∞^∑(n=1) a_n are particularly ugly and hard to read, and do not make sense when parsed according to standard rules for reading mathematical expressions.
 
Ray Vickson said:
If you are going to use plain text, it is better to write your summations as something like sum_{n=1 ..∞} a_n or sum(a_n: n=1..∞), and you can, of course, replace the word "sum" by the symbol Σ. Constructions like your ∞^∑(n=1) a_n are particularly ugly and hard to read, and do not make sense when parsed according to standard rules for reading mathematical expressions.

Thanks, I'll keep that in mind if something else comes up. The next time I post, I'll try and use LaTeX for the equations; although, I need to learn how to use it first.
 
CricK0es said:
Thanks, I'll keep that in mind if something else comes up. The next time I post, I'll try and use LaTeX for the equations; although, I need to learn how to use it first.

There are tutorials available in this Forum, but perhaps the easiest way is to look at someLaTeX statements of others. For example, you can write ##\pi^3/2 + \sum_{n=1}^{\infty} (-1)^n 4 / n^2 \cos(nx)## or ##\pi^3/2 + \sum_{n=1}^{\infty} (-1)^n 4 / n^2 \cos nx## for an in-line expression and
$$\sum_{n=1}^{\infty} (-1)^n \frac{4}{n^2} \cos (nx) \; \text{or} \; \sum_{n=1}^{\infty} (-1)^n \frac{4}{n^2} \cos nx$$
for a displayed expression.

To see the constructions used, just double right-click on the image and ask for a display of math as tex. The in-line version is initiated and terminated by "# #" (with space between the two #s removed), so # # some formula # #. The displayed version uses "$ $" instead (again, with no spaces between the two $s). Note in particular the use of "\cos" instead of "cos"; try it both ways and see why.
 
  • Like
Likes   Reactions: CricK0es
Ray Vickson said:
There are tutorials available in this Forum, but perhaps the easiest way is to look at someLaTeX statements of others. For example, you can write ##\pi^3/2 + \sum_{n=1}^{\infty} (-1)^n 4 / n^2 \cos(nx)## or ##\pi^3/2 + \sum_{n=1}^{\infty} (-1)^n 4 / n^2 \cos nx## for an in-line expression and
$$\sum_{n=1}^{\infty} (-1)^n \frac{4}{n^2} \cos (nx) \; \text{or} \; \sum_{n=1}^{\infty} (-1)^n \frac{4}{n^2} \cos nx$$
for a displayed expression.

To see the constructions used, just double right-click on the image and ask for a display of math as tex. The in-line version is initiated and terminated by "# #" (with space between the two #s removed), so # # some formula # #. The displayed version uses "$ $" instead (again, with no spaces between the two $s). Note in particular the use of "\cos" instead of "cos"; try it both ways and see why.

I see. I'll have a play around with it and see what I can do. Thank you
 

Similar threads

  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 14 ·
Replies
14
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 16 ·
Replies
16
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 6 ·
Replies
6
Views
2K
Replies
3
Views
2K
Replies
3
Views
2K