Find the images of the following function

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The discussion centers on understanding the graph of a specific function, focusing on its characteristics and behavior. The value of the function at x=0 is identified as the maximum output, which is crucial for determining the graph's peak. The graph exhibits symmetry about the x=0 axis, indicating that it behaves identically on both sides of the y-axis. Additionally, the presence of x in the denominator prevents the function from reaching infinity, as it is undefined at that point. Overall, these elements are essential for accurately interpreting the function's graph.
angela107
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Homework Statement
I found the image of the following function (a graph). The question also asks me to explain my answer briefly. I'm not sure how to go about to answering.
Relevant Equations
n/a
Screen Shot 2020-09-29 at 6.13.50 PM.png


Screen Shot 2020-09-29 at 6.17.38 PM.png
 
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angela107 said:
Homework Statement:: I found the image of the following function (a graph). The question also asks me to explain my answer briefly. I'm not sure how to go about to answering.
Relevant Equations:: n/a

View attachment 270198

View attachment 270199
So just start talking about how the equation produces the graph. What is the value of the function with x=0? Why is that the maximum that the function can produce? Why is the graph symmetric about the x=0 axis? With an x in the denominator, why is the function not equal to infinity somewhere?
 
berkeman said:
So just start talking about how the equation produces the graph. What is the value of the function with x=0? Why is that the maximum that the function can produce? Why is the graph symmetric about the x=0 axis? With an x in the denominator, why is the function not equal to infinity somewhere?
Thank you!
 
angela107 said:
Thank you!
You're welcome. And your thoughts are... :smile:
 
I tried to combine those 2 formulas but it didn't work. I tried using another case where there are 2 red balls and 2 blue balls only so when combining the formula I got ##\frac{(4-1)!}{2!2!}=\frac{3}{2}## which does not make sense. Is there any formula to calculate cyclic permutation of identical objects or I have to do it by listing all the possibilities? Thanks
Since ##px^9+q## is the factor, then ##x^9=\frac{-q}{p}## will be one of the roots. Let ##f(x)=27x^{18}+bx^9+70##, then: $$27\left(\frac{-q}{p}\right)^2+b\left(\frac{-q}{p}\right)+70=0$$ $$b=27 \frac{q}{p}+70 \frac{p}{q}$$ $$b=\frac{27q^2+70p^2}{pq}$$ From this expression, it looks like there is no greatest value of ##b## because increasing the value of ##p## and ##q## will also increase the value of ##b##. How to find the greatest value of ##b##? Thanks

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