Find the impedance of capacitor and inductor with dependant current so

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Discussion Overview

The discussion revolves around finding the impedances of a capacitor and an inductor in a circuit with a dependent current source. Participants explore the relevant formulas and calculations, addressing the relationships between voltage, current, and impedance.

Discussion Character

  • Homework-related
  • Technical explanation
  • Debate/contested

Main Points Raised

  • One participant suggests converting the current source into polar form and calculating the voltage across a resistor to find the capacitor's impedance, resulting in Zc = -j10.
  • Another participant challenges the initial approach, emphasizing the need to include the correct formulas for capacitor and inductor impedance.
  • Participants clarify that the impedance of a capacitor is given by Zc = j(-1/ωC) and for an inductor by ZL = jωL, where ω is the angular frequency.
  • There is a discussion about the relationship between voltage and current, with one participant noting that the impedance is the ratio of voltage to current and does not depend solely on either quantity.
  • One participant expresses confusion about the voltage across the capacitor, stating that the current from the source does not all go through the resistor, which affects the calculation.
  • Another participant confirms that the angular frequency is constant throughout the circuit and is crucial for determining impedance.

Areas of Agreement / Disagreement

Participants express differing views on the correct approach to calculating the voltage across the capacitor and the implications of the current source on the circuit. There is no consensus on the initial calculations, and some points remain contested.

Contextual Notes

Participants note that the voltage across the capacitor is not necessary for determining its impedance, and there is an emphasis on the importance of angular frequency in the calculations. Some assumptions about the circuit's behavior and the distribution of current are not fully resolved.

pokie_panda
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Homework Statement



From the circuit find the impedances of the capacitor and inductor

attachment.php?attachmentid=58273&stc=1&d=1367084378.jpg


Is(t)=15 cos(500t) A


Homework Equations





The Attempt at a Solution



So is this right? Convert the 15 cos 500t into polar form, 15<0 I. Then the resistor is 8 ohms, so 15*8 = 120 V.

Therefore, to find the impedance capacitor is

v(t)=120 cos(500t)
Zc= -1/(0.2*10^-3 * 500)
=-j10

but now I'm stuck. How do find grad is(t)?
 

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No, that's not right. I suggest you start by telling us what the formulas are for the impedance of a capacitor and an inductor are, which you should have included in the relevant equations.
 
The relevant equations

Capacitor Impedance= j(-1/wC) using v(t)
Inductor impedance = (jwL) using i(t)

This equations for capacitor you need voltage could even using the i(t)= 15 cos 500t you still get
Zc as= -j10.
 
Last edited:
What do you mean "using v(t)" and "using i(t)"? Neither v nor i appear in the formulas. What does ##\omega## stand for?
 
v(t), i(t) are the functions and w is the angular frequency

for example

C= 2uf
v(t)=200cos(5t) mV

Zc= j *-1/((2*10^-6 )(5))
 
Is this the right assumption to make we know that the current is going to be the same,
So
Zc= j -1/(500*(0.2*10^-3))
=-j10
2.5*15 cos(500t) the frequency should be the same ?
ZL=j*500*(10*10-3)
=j.5
 
Sorry, brain fart on my part. Your answer for Zc is correct.

Remember that the impedance is the ratio of voltage and current: Z = V/I. It doesn't depend on either V or I; it depends on both. The voltage across an element and the current flowing through it will always have the same frequency. The impedance simply changes the amplitude and phase of the sine wave.

So what did you mean by "grad is(t)"?
 
sorry i should of said delta , its the current across the capacitor.
So this should have a angular frequency of 500
 
I should clarify a bit. The way you determined the voltage across the capacitor wasn't correct. The current from the current source doesn't all go through the resistor, so you can't find the voltage across the resistor simply by multiplying is(t) by R.

In this problem it doesn't matter because you don't need the voltage across the capacitor. All you need to know is the angular frequency, which is constant throughout the circuit.
 
  • #10
pokie_panda said:
sorry i should of said delta , its the current across the capacitor.
So this should have a angular frequency of 500

That's right.
 
  • #11
Thanks for the help, sorry for posting in the wrong area.
 

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