From the circuit find the impedances of the capacitor and inductor
Is(t)=15 cos(500t) A
The Attempt at a Solution
So is this right? Convert the 15 cos 500t into polar form, 15<0 I. Then the resistor is 8 ohms, so 15*8 = 120 V.
Therefore, to find the impedance capacitor is
Zc= -1/(0.2*10^-3 * 500)
but now I'm stuck. How do find grad is(t)?
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