Find the limit of (sqrt(1+2x) - sqrt(1+3x))/(x + 2x^2) as x->0

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I'm having a lot of trouble making any progress on this limit. If someone could give me a direction to get started I would appreciate it.

\lim_{x{\rightarrow}0}\frac{\sqrt{1+2x}-\sqrt{1+3x}}{x+2x^2}
 
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Use L'Hopitals Rule.
 
Or you could multiply by the conjugate of the numerator. (ie, sqrt(1+2x)+sqrt(1+3x)).
 
Go with StatusX's advice if L'Hopitals Rule wasn't taught yet because then it wouldn't be appropriate.

If you haven't learned L'Hopitals Rule, I recommend to learn it and use it to check your answer

Also, you can always test it numerically. I do that sometimes just to be 100% certain. I would try something like x=0.01, 0.001 and 0.0001.
 
As stated above, L'Hopital's rule, or, if that's not allowed, rationalize the numerator.
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...

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