Find the Limit of X and Y Exponents as n Goes to Infinity

jinbaw
Messages
65
Reaction score
0

Homework Statement



X \geq Y &gt; 0, find \lim_{n \to \infty} \left(\frac{2X^n + 7Y^n}{2}\right)^{1/n}<br />

Homework Equations





The Attempt at a Solution


I'm not really sure how to do it, but i guess I need to use the fact that \frac{Y}{X} \leq 1, and so \lim_{n \to \infty} \left(\frac{Y}{X}\right)^n = 0.
Thanks for your help.
 
Physics news on Phys.org
Multiply the argument by \frac{X^n}{X^n} then take the X^n out of the brackets.
 
\lim_{n \to \infty} X \left( 1 + \left( \frac{7Y}{2X} \right)^n \right)^{1/n}
But I'm still stuck on how to procceed, if you could help.
 
There is one mistake, 7/2 should not be within the brackets. Now take X in front of the limit and use \frac{Y}{X} \leq 1 \Rightarrow \lim_{n \to \infty} \left(\frac{Y}{X}\right)^n = 0.
 
Oh right.. So its limit is X.
Thanks :-D
 
That's right!
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...

Similar threads

Back
Top