find the magnitude and direction of the final velocity

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Homework Help Overview

The problem involves two vehicles colliding at a right angle intersection, with a focus on determining the magnitude and direction of their final velocity after the collision. The mass ratio of the vehicles is given as 1:4, and both vehicles approach the intersection at a speed of 13 m/s.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the calculation of the x and y components of velocity based on the mass ratio and initial speeds. There is an exploration of potential calculation errors and a request for clarification on the steps taken to arrive at the results.

Discussion Status

The discussion is ongoing, with some participants confirming the calculations and suggesting that the original poster may have made a minor error. There is a lack of consensus on the correctness of the results, as one participant suggests seeking further clarification from a teacher.

Contextual Notes

Participants are working under the constraints of the problem statement and the provided mass and speed values. The original poster's results do not match the multiple-choice options given, leading to further questioning of the calculations.

bigboss
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Homework Statement



Two vehicles approach a right angle intersection and then collide. After the collision, they become entangled. If their mass ratios were 1:4 and their respective speeds as they approached were both 13 m/s, find the magnitude and direction of the final velocity of the wreck.

A)16.3 m/s at 79° B)13.1 m/s at 79° C)15.7 m/s at 79° D)12.5 m/s at 79°

Homework Equations


p=mv. m1v1+m2v2=(m1+m2)vf


The Attempt at a Solution



i found both x and y compontents of the cars, with one car having a mass of 1 kg and another having a mass of 4kg. I ended up getting, 10.7m/s and 76 degrees, but that is not even a choice
 
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Sounds like you're on the right track. Possibly you have just made a little calculation error somewhere. Can you show us what you did?
 


since it is a right angle, one car is going 13 m/s right, while the other is going 13m/s up

so there is a 1:4 ratio of mass

x component) m1v1+m2v2=(m1+m2)v

1(13)+(4*0)=(1+4)V
13/5= vx
vx=2.6 m/s

y component) m1v1+m2v2=(m1+m2)v

(1*0)+(4*13)=(1+4)v
52/5=vy
vy=10.4 m/s

sqrt 10.4^2+2.6^2
= 10.7 m/s
inverse tan of 10.4/2.6= 76 degrees
 


Frankly, I do not see the error.
I did the calculation myself and I found the same answer.

Perhaps you should go see your teacher and ask him what is wrong with your answer because you absolutely don't see it and have checked it multiple times (that's a polite way of asking if he's sure he isn't wrong :smile:)
 

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