- #1

- 27

- 0

## Homework Statement

Find the magnitude of the torque about P if a 68 lb force is applied as shown. Give your answer correct to the nearest integer.

## Homework Equations

t=r X F

## The Attempt at a Solution

t = (4)(68)(sin30)

= 136

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- #1

- 27

- 0

Find the magnitude of the torque about P if a 68 lb force is applied as shown. Give your answer correct to the nearest integer.

t=r X F

t = (4)(68)(sin30)

= 136

- #2

Homework Helper

- 3,121

- 6

Don't you want to consider the distance at which it is acting is 4*√2 ?

At the point of interaction then the ⊥ component of F looks to me like F*Cos15°

- #3

- 2,412

- 712

## Homework Statement

Find the magnitude of the torque about P if a 68 lb force is applied as shown. Give your answer correct to the nearest integer.

## Homework Equations

t=r X F

## The Attempt at a Solution

t = (4)(68)(sin30)

= 136

You wrote what must have been intended to be a vector equation for the torque, t = r x F, because the cross product only makes sense if t, r, and F are all expressed as vectors. But then you proceeded to do a scalar calculation. Why not make your torque calculation in vector form using the determinant expression for the cross product and giving the resulting torque as a vector? Then if you need the magnitude of that vector, dot it with itself and take the square root of the result.

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