Find the p.d.f of y from p.d.f of x

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Homework Statement



fx(X) ={ 1/4 0 < x < 1,
{ 3/8 3 < x < 5,
{ 0 otherwise

Let Y = 1/X. Find the probability density function fy (y) for Y .

Homework Equations





The Attempt at a Solution



Fy(x)=P(Y<x)=P(1/X<x)=P(X>1/x)..

i can't go over more than this
 
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What's the relationship between P(X<x) and P(X>x) for a continuous distribution.
 
wldnrp13579 said:

Homework Statement



fx(X) ={ 1/4 0 < x < 1,
{ 3/8 3 < x < 5,
{ 0 otherwise

Let Y = 1/X. Find the probability density function fy (y) for Y .

Homework Equations





The Attempt at a Solution



Fy(x)=P(Y<x)=P(1/X<x)=P(X>1/x)..

i can't go over more than this

You have the probability density of X. What is stopping you from computing G(t) =P(X > t)?
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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