Find the sum to infinite series

AI Thread Summary
The discussion focuses on finding the sum of the infinite series cot^-1(3) + cot^-1(7) + cot^-1(13) and attempts to define the nth term as t_n = cot^-1(2^n + (2n-1)). Participants express confusion regarding the generalization of the series' terms, particularly how the sequence 3, 7, 13 is derived. There are suggestions to clarify notation for better understanding, such as using parentheses or the term "arccot." The main challenge highlighted is the difficulty in calculating the limit as n approaches infinity.
utkarshakash
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Homework Statement


cot^-1 3 + cot^-1 7 + cot^-1 13+...


Homework Equations



The Attempt at a Solution



I first tried to write the nth term of the series

t_n = cot^{-1}\left( 2^n + (2n-1) \right)

Then I tried to calculate the limit as n→∞. But I simply can't do that. I mean I don't know how to calculate the limit.
 
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utkarshakash said:

Homework Statement


cot^-1 3 + cot^-1 7 + cot^-1 13+...


Homework Equations



The Attempt at a Solution



I first tried to write the nth term of the series

t_n = cot^{-1}\left( 2^n + (2n-1) \right)

Then I tried to calculate the limit as n→∞. But I simply can't do that. I mean I don't know how to calculate the limit.

Your presentation is very confusing; use parentheses, like this:
cot^(-1)(3) + cot^(-1)(7) + ... or use "arccot" instead of "cot^-1".
 
Ray Vickson said:
Your presentation is very confusing; use parentheses, like this:
cot^(-1)(3) + cot^(-1)(7) + ... or use "arccot" instead of "cot^-1".

OK Here's it

cot^{-1} 3 + cot^{-1} 7 + cot^{-1} 13+...
 
utkarshakash said:
t_n = cot^{-1}\left( 2^n + (2n-1) \right)
It's not at all obvious to me how 3, 7, 13.. is supposed to be generalised. Do you know that it is intended to be 2n+2n-1, or are you guessing?
 
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