Find the Tangent of y=1/(x-1) with Slope -1

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Find an equation for the tangent to the curve y=1/(x-1) that has slope -1.
 
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Ok you have y, you know that y'=-1. Is there a way you can find a point x where this happens?
 
If y= 1/(x-1)= (x-1)-1, what is y'? (I hereby give you permission to use (xn)'= nxn-1!)
 
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