- #1
ahmed elshimy
- 3
- 0
- Homework Statement
- Find r2 , v1 , v2 , v3 , It
- Relevant Equations
- It = i1 = i2 = i3
V1 + v2 + v3 = E
How i can find r2 value in this circuit?
R1 = 2
R3 = 5
E = 20v
R1 = 2
R3 = 5
E = 20v
Is there a way to actually solve it?Joshy said:It looks like you already know that the same current is flowing through all of those resistors since they are in a series; you also have your equation above. Great job! $$I = i_1 = i_2 = i_3$$.
You've gotten to the next step using KVL. Great job there too! $$v_1 + v_2 + v_3 = E$$.
Just like a regular mathematics problem where you want to isolate the variable of interest... I would solve for v_{2} and apply an equation that relates resistance (R_{2}) to voltage (v_{2}) and current (I).
Are you given the value of I? You would need either I or the value of R2 to solve for the voltages and currents, it would seem. Did you copy the question exactly?ahmed elshimy said:Is there a way to actually solve it?
Or can't solve because didn't have any i or p ?
berkeman said:Are you given the value of I? You would need either I or the value of R2 to solve for the voltages and currents, it would seem. Did you copy the question exactly?
A series circuit is an electrical circuit in which the components are connected in a single loop, with the current flowing through each component in a sequential manner.
To find the unknown resistance in a series circuit, you can use Ohm's Law, which states that resistance (R) is equal to the voltage (V) divided by the current (I). So, R = V/I.
You will need a power supply, a voltmeter, an ammeter, and the unknown resistor in order to calculate the resistance in a series circuit.
Finding the unknown resistance in a series circuit is important for understanding the behavior of the circuit and determining the appropriate components to use for a desired electrical outcome.
No, the method for finding the unknown resistance in a series circuit is different from that of a parallel circuit. In a parallel circuit, the total resistance is calculated by adding the reciprocals of the individual resistances, rather than simply summing them.