jaychay
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Can you please help me ?
I have tried to do it but I end up getting the wrong answer.
I have tried to do it but I end up getting the wrong answer.
Can you tell me where did 18 pi come from ?skeeter said:$\displaystyle V = 18\pi - 2\pi \int_0^{\pi/2} x \cos{x} \, dx$
$\displaystyle V = 18\pi - \pi \int_0^1 [\arccos{y}]^2 \, dy$
jaychay said:Can you tell me where did 18 pi come from ?