SammyS
Staff Emeritus
Science Advisor
Homework Helper
- 11,987
- 1,579
Those actually should written be something likeHelly123 said:X (theta) must be on 4 Quadrant, so 2x must on 8 quadrants, 540<2x<=720
X 1=5/4 π
X2 = 7/4 π
Both added 2π to get x at 8 quadrants
X1 = 13/4 π
X2 = 15/4 π
Both satisfied the domain
How to decide which one is the answer?
2x1 = (5/4) π
2x2 = (7/4) π
Then adding 2π gives (two new possibilities for x):2x2 = (7/4) π
2x3 = (13/4) π
2x4 = (15/4) π
2x4 = (15/4) π
Solve for each xk .