Find theta given known cos and sin....

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SUMMARY

The discussion focuses on determining the angle θ given known values of sine and cosine, specifically using the equation cos(2θ) = cos²(θ) - sin²(θ). Participants clarify that the condition provided in the problem is impossible, as it leads to conflicting angle values. The correct angles derived from the equations are θ = 7π/8 and 2θ = 15π/4, with the understanding that θ must be in the fourth quadrant due to the signs of sine and cosine. The conversation emphasizes the importance of correctly interpreting the quadrant restrictions and the implications of angle periodicity.

PREREQUISITES
  • Understanding of trigonometric identities, specifically cos(2θ) = cos²(θ) - sin²(θ)
  • Knowledge of angle quadrants in the unit circle
  • Familiarity with the concepts of periodicity in trigonometric functions
  • Ability to perform algebraic manipulation of trigonometric equations
NEXT STEPS
  • Study the unit circle and the properties of angles in different quadrants
  • Learn about the implications of periodicity in trigonometric functions
  • Explore the use of inverse trigonometric functions such as arcsin and arccos
  • Practice solving trigonometric equations with restrictions on angle values
USEFUL FOR

Students studying trigonometry, mathematics educators, and anyone interested in solving trigonometric equations with angle restrictions.

  • #31
Helly123 said:
X (theta) must be on 4 Quadrant, so 2x must on 8 quadrants, 540<2x<=720
X 1=5/4 π
X2 = 7/4 π
Both added 2π to get x at 8 quadrants
X1 = 13/4 π
X2 = 15/4 π

Both satisfied the domain
How to decide which one is the answer?
Those actually should written be something like
2x1 = (5/4) π
2x2 = (7/4) π​
Then adding 2π gives (two new possibilities for x):
2x3 = (13/4) π
2x4 = (15/4) π​

Solve for each xk .
 
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