Find torque of a ball on the end of a light rod

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Homework Help Overview

The problem involves a small ball attached to a light rod, rotating in a horizontal circle. It requires calculating the moment of inertia and the torque necessary to maintain constant angular velocity while accounting for air resistance.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants discuss the calculation of moment of inertia and the relationship between torque and air resistance. Questions are raised about how to correlate force and torque.

Discussion Status

Some participants have confirmed the moment of inertia calculation, while others are exploring the forces acting on the system at constant angular velocity. Guidance has been offered regarding the relationship between torque and the forces involved.

Contextual Notes

There is a mention of uncertainty regarding the formula for torque and the effects of air resistance on the system. Participants are also considering the implications of maintaining constant angular velocity.

mathcrzy
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Homework Statement



A small 1.25 kg ball on the end of a light rod is rotated in a horizontal circle of radius 0.890 m.
(a) Calculate the moment of inertia of the system about the axis of rotation.
____kg*m^2
(b) Calculate the torque needed to keep the ball rotating at constant angular velocity if air resistance exerts a force of 0.0800 N on the ball.
____m*N

Homework Equations



a) kg*m^2
b) kg*m^2-air resistance (dont know the formula; just a guess)

The Attempt at a Solution



a) 1.25*.89^2=.99kg*m^2 (i was able to figure out this answer)
b) 1.25*.89^2-.08=.91m*N
 
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Hint: air resistance is a force, you are required to find torque. how do u corelate them?
 
Do you know how to find find the Moment of inertia?
 
You got the moment of inertia right.
Carefully consider what forces it faces when moving at constant angular velocity.
 
Find the torque which is applied by the air on the object.The same amount of torque should be applied in the opposite direction in the opposite direction.

Torque = force * radius
 

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