Find total resistance in mixed circuit

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Homework Help Overview

The discussion revolves around calculating the total resistance in a mixed circuit involving resistors in both series and parallel configurations. The resistors have specified values, and participants are attempting to apply relevant equations for series and parallel resistances.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants are sharing their calculations for the total resistance, questioning the accuracy of their methods, and seeking clarification on the arrangement of resistors in series and parallel.

Discussion Status

There is an ongoing exchange of calculations and corrections, with some participants pointing out errors in the application of formulas. Guidance has been offered regarding the correct interpretation of series and parallel connections, but no consensus has been reached on the final resistance value.

Contextual Notes

Participants are working under a time constraint, as the assignment is due soon. There are indications of confusion regarding the arrangement of resistors and the application of the formulas for calculating equivalent resistance.

Princess19
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Homework Statement



http://img59.imageshack.us/img59/9321/photo2100.jpg

R1 = R2 = R3 = 5 ohms
R4 = R5 = R6 = 10 ohms
R7 = 20 ohms

Homework Equations



1/Rp = 1/R1 + ... +1/Rn (parallel)
Rs = R1 +...+Rn (series)

The Attempt at a Solution



Here's what I've got so far. I need help this is due tomorrow. :(

R67 = 10 + 20 = 30 ohms

1/R567 = 1/10 + 1/30 = 7.5 ohms

R4567 = 10 + 7.5 = 17.5 ohms

1/R34567 = 1/5 + 1/17.5 = 4 ohms

R234567 = 5 + 4 = 9 ohms

1/R1234567 = 1/5 + 1/9 = 3 ohms


okay, now tell me where I am wrong!

Thanks a bunch!
 
Last edited by a moderator:
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Princess19 said:

Homework Statement



http://img59.imageshack.us/img59/9321/photo2100.jpg

R1 = R2 = R3 = 5 ohms
R4 = R5 = R6 = 10 ohms
R7 = 20 ohms

Homework Equations



1/Rp = 1/R1 + ... +1/Rn (parallel)
Rs = R1 +...+Rn (series)

The Attempt at a Solution



Here's what I've got so far. I need help this is due tomorrow. :(

R67 = 10 + 20 = 30 ohms

1/R567 = 1/10 + 1/30 = 7.5 ohms

R4567 = 10 + 7.5 = 17.5 ohms

1/R34567 = 1/5 + 1/17.5 = 4 ohms

R234567 = 5 + 4 = 9 ohms

1/R1234567 = 1/5 + 1/9 = 3 ohms


okay, now tell me where I am wrong!

Thanks a bunch!

First, to be accurate,

1/R567 = 1/10 + 1/30 = 7.5 ohms should be 1/R567 = 1/10 + 1/30 = 1/7.5 ohms

Next, this is correct:

R4567 = 10 + 7.5 = 17.5 ohms

But then, R3 is in series with this value, not in parallel...
 
Last edited by a moderator:
berkeman said:
First, to be accurate,

1/R567 = 1/10 + 1/30 = 7.5 ohms should be 1/R567 = 1/10 + 1/30 = 1/7.5 ohms

Next, this is correct:

R4567 = 10 + 7.5 = 17.5 ohms

But then, R3 is in series with this value, not in parallel...

oh, 7.5 ohms is already the reciprocal of the answer i got which was .1333

oh, why is it in series? arent they facing each other?
 
Princess19 said:
oh, 7.5 ohms is already the reciprocal of the answer i got which was .1333

oh, why is it in series? arent they facing each other?

R3 is in series with the 4567 total, and that is in parallel with R2.

In fact, I would have just added the series combination of R4 + R3 + R567 as a single step.

When two resistors are next to each other and connected with shorts at both ends, they are in parallel. When they are connected with a resistor at one end, all 3 of those resistances are in parallel (nose-to-tail).
 
R67 = 10 + 20 = 30 ohms

1/R567 = 1/10 + 1/30 = 7.5 ohms

R4567 = 10 + 7.5 = 17.5 ohms

R34567= 5 + 17.5 = 22.5 ohms

1/R234567 = 1/5 + 1/22.5 = 4 ohms

R1234567 = 5 + 4 = 7 ohms

how about now?
 
Princess19 said:
R67 = 10 + 20 = 30 ohms

1/R567 = 1/10 + 1/30 = 7.5 ohms

R4567 = 10 + 7.5 = 17.5 ohms

R34567= 5 + 17.5 = 22.5 ohms

1/R234567 = 1/5 + 1/22.5 = 4 ohms

R1234567 = 5 + 4 = 7 ohms

how about now?

That looks good, except you keep doing that shortcut with the parallel addition.

1/R567 = 1/10 + 1/30 = 7.5 ohms Needs to be 1/R567 = 1/10 + 1/30 = 1/7.5 ohms

(so R567 = 7.5 Ohms)

And

1/R234567 = 1/5 + 1/22.5 = 4 ohms Needs to be 1/R234567 = 1/5 + 1/22.5 = 1/4 ohms

(so R234567 = 4 Ohms).
 
Thanks for your help! :)
 

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