Excellent! Thank you.
Now, tiny-tim, what in the world are you talking about? I'm afraid I dont' see your point either.
I would probably use "brute strength"
If y= sin(sin(x)), then y'= -cos(sin(x))(-cos(x))= cos(x)cos(cos(x)). Now, instead of actually doing the other derivatives (because they get really messy!), use the fact that the nth derivative of (f(x)g(x)) will be \sum _nC_i f^{i}g^{n-i} to see that we will, after three more derivatives, have a sum of 4 terms with binomial coeficients times sin and cos- and the largest possible value for sine or cosine is 1.