Find Volume of Metal Object: 860-785 N, 9.8 m/s^2

  • Thread starter Thread starter srhly
  • Start date Start date
  • Tags Tags
    Stuck
AI Thread Summary
The volume of the metal object can be determined using Archimedes' principle and the readings from a spring scale. The scale shows 860 N in air and 785 N when submerged, indicating a buoyant force of 75 N. This buoyant force equals the weight of the water displaced, allowing the use of the formula Fb = ρVg. By substituting the values, the volume is calculated to be 0.00765 m^3. Thus, the volume of the metal object is 0.00765 m^3.
srhly
Messages
17
Reaction score
0
A metal object is suspended from a spring scale. The scale reads 860 N when the object is suspended in air, and 785 N when the object is completely submerged in water.
The acceleration due to gravity is 9.8 m/s^2.
Find the volume of the object. Answer in m^3.
 
Physics news on Phys.org
What does Archimedes principle tell you?
 


To find the volume of the metal object, we can use the principle of buoyancy. The difference in the scale readings (860 N - 785 N = 75 N) represents the buoyant force acting on the object when it is submerged in water. This buoyant force is equal to the weight of the water displaced by the object.

We can use the formula Fb = ρVg, where Fb is the buoyant force, ρ is the density of water (1000 kg/m^3), V is the volume of the object, and g is the acceleration due to gravity (9.8 m/s^2).

Substituting the given values, we get 75 N = (1000 kg/m^3) V (9.8 m/s^2).

Solving for V, we get V = 0.00765 m^3.

Therefore, the volume of the metal object is 0.00765 m^3.
 
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top