Find Width of Slit for Diffraction Maxima

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    Diffraction Maxima
AI Thread Summary
To find the width of the slit in a single-slit diffraction problem, the relevant parameters include the wavelength of light (650 nm) and the distance between the first-order maxima (2.05 mm) on a screen 2.00 m away. The slit width can be approximated using the formula a*sin(Θ)=(m+0.5)λ for maxima, but the exact position of maxima requires differentiation of the intensity function. Initial attempts to calculate the slit width using both maxima and minima formulas yielded incorrect results. Clarification on the correct equation to use for finding the slit width is sought, emphasizing the need for precise calculations in diffraction scenarios. The discussion highlights the complexities involved in accurately determining diffraction maxima.
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Homework Statement


A single slit diffracts laser light of wavelength 650 nm onto a screen 2.00 m away. The distance between the two first-order maxima on either side of the central peak is 2.05 mm. How wide is the slit?

Homework Equations


a=width of slit
y=distance from central max to specific spot
L=distance of screen from the slit
λ=wavelength of light
sinΘ≈Θ=y/L
minima occurs at: a*sinΘ=mλ
(found on internet) approximation of maxima occurs at: a*sinΘ=(m+.5)λ

The Attempt at a Solution


L=2m
λ=650*10^-9m
each maxima is the same distance from the central maxima so if the distance between the 2 first order maxima is .00205m then
y=.001025m

a*(.001025/2)=(1.5)(650*10^-9)
I found answer to be 0.001902m (wrong)

just in case I decided to try and see using the minima formula a*(.001025/2)=(650*10^-9)
answer :0.001268m (wrong)

any assistance would be great.
 
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The maximum of the sinc function is not at m+0.5 . It's close, but not exactly.
 
Khashishi said:
The maximum of the sinc function is not at m+0.5 . It's close, but not exactly.
what equation should I use then?
 
You differentiate the intensity expression...
 
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