Find x for Summation Series Convergence

  • Thread starter Thread starter cloveryeah
  • Start date Start date
  • Tags Tags
    Series Summation
cloveryeah
Messages
25
Reaction score
0

Homework Statement



Σ ( x^n/ln(n+5) )
n=1

find the value of x that the above series converges

Homework Equations

The Attempt at a Solution


i cal. it by ratio test
and i found that |x|<1

but when i input (-1,1) into my webwork...it said it's wrong[/B]
 
Physics news on Phys.org
cloveryeah said:

Homework Statement



Σ ( x^n/ln(n+5) )
n=1

find the value of x that the above series converges

Homework Equations

The Attempt at a Solution


i cal. it by ratio test
and i found that |x|<1

but when i input (-1,1) into my webwork...it said it's wrong[/B]

Your answer may be overly conservative. You need to look at whether the series converges or diverges at x = +1 and at x = -1.
 
Hi Cloveryeah,
Great work, just something you've missed
In order for the series to converge,
Whenver n→∞ (x^n/ln(n+5)) = 0
You said that |x| < 1, you can't try x= 1 or x = -1, it's strictly less not even equal
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...

Similar threads

Replies
3
Views
1K
Replies
5
Views
1K
Replies
1
Views
1K
Replies
6
Views
1K
Replies
22
Views
4K
Replies
2
Views
2K
Back
Top