Finding Acceleration on 30° Downward Slope w/ 0.10 Coeff. of Friction

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SUMMARY

The acceleration of a runner descending a 30° slope with a coefficient of kinetic friction of 0.10 can be calculated using the formula a = g * (sin(θ) - μ * cos(θ)). In this case, the acceleration is determined to be approximately 2.45 m/s². The net force (Fnet) is derived from the difference between the gravitational force acting down the slope and the frictional force opposing the motion. The discussion confirms that the initial calculation method is valid, while also exploring alternative approaches to arrive at the same result.

PREREQUISITES
  • Understanding of Newton's second law of motion
  • Knowledge of trigonometric functions (sine and cosine)
  • Familiarity with the concept of friction and its coefficients
  • Basic algebra for solving equations
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  • Study the derivation of net force in inclined plane problems
  • Learn about the effects of varying coefficients of friction on acceleration
  • Explore advanced applications of Newton's laws in real-world scenarios
  • Investigate the role of angle in determining forces on inclined surfaces
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Physics students, educators, and anyone interested in understanding the dynamics of motion on inclined planes and the effects of friction on acceleration.

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Homework Statement



A person is running down a hill which is a 30° downward slope. If the coefficient of kinetic friction is 0.10, what is acceleration of the runner.

Homework Equations



Fnet=F┴-Ff


The Attempt at a Solution



Since we are only given 2 known things, the θ is 30° and the kinetic friction is 0.10. I am wondering if I am using the correct formula and need to be pointed in direction of what else to find to actually find the acceleration. I know we need Fnet but that is not all.
 
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Ok I have found out the answer one way by just doing a = 9.81 x (0.5-0.10(0.866)) but is there a different way to find the answer or is this the only one? I mean by finding Fnet and somehow answering it a different way?
 

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