Finding an unknown resistance in an Electric Circuit

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SUMMARY

The discussion revolves around calculating an unknown resistance in an electric circuit where two resistors are connected in series and parallel to a 110-V line. The known resistor is 2.0 kΩ, and the power consumed in series is one-fourth that consumed in parallel. The key equations used include the total resistance formulas for series and parallel configurations, as well as the power formula. The correct approach involves setting the power equations for both configurations equal and solving for the unknown resistance.

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mlostrac
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Homework Statement


When connected in series to a 110-V line, two resistors use one-fourth the power
that is used when they are connected in parallel. If one resistor is
2.0 kΩ, what is the resistance of the other?


Homework Equations


1/Rt = 1/R1 +1/R2 (total resistance in parallel)
Rt = R1 + R2 (resistance in series)

Power = Current x Voltage


The Attempt at a Solution



So far my attempts have fizzled, ending with negative numbers.

Heres what I did:
1) Set the two hypothetical circuits (series and parallel) equal to each other by isolating the power:

P1 = 110^2/0.25(R1+R2)
P2 = 110^2(R1+R2)

And then isolating for R2 and solving (since we have R1 = 2000 ohms)

I ended up doing the quadratic equation and getting two negative numbers...

Any help would be appreciated :)
 
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mlostrac said:
P1 = 110^2/0.25(R1+R2)
Can you show why it this true?
P2 = 110^2(R1+R2)
The term R1+R2 must be in the denominator.

Anyway, I suggest that you work this symbolically. Find expressions

Pseries = V2/Req,series
Pparallel = V2/Req,parallel
then take the ratio and say
Pseries/Pparallel = 1/4.
 
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