Finding angle to reduce friction

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The discussion revolves around calculating the banking angle required for a car traveling at 60 mph around a 500 ft radius curve without relying on friction. The participant expresses uncertainty about their solution and the validity of their assumptions, particularly regarding the forces acting on the car, including normal force, centripetal force, and friction. They seek clarification on their equations and force diagram, acknowledging a potential misunderstanding of the components of centripetal acceleration. Feedback indicates that while the force diagram is mostly correct, the application of Newton's second law (F=ma) needs adjustment due to the horizontal nature of centripetal acceleration. The conversation emphasizes the importance of correctly analyzing forces in circular motion to find the appropriate banking angle.
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Homework Statement



A car is traveling around a curve that has a radius of 500 ft. at a speed of 60mph. To what angle must the curve be banked so that there is no frictional force?

Homework Equations


The Attempt at a Solution



I have attached mt solution below. I don't know the right answer to this question but I gave it a shot. The answer I got doesn't seem weird or anything so it has a a chance of being right. I don't think I understand the concept completely so I don't know if the moves or assumptions I made are valid. I kind of just wrote down the equations I know that might be relevant and used those. I know circular motion has acceleration proportional to the square of the speed and the radius so I used that equation. I am just not sure if my diagrams are correct and if I'm allowed to set equal the things that I set equal. So could you guys point out what is wrong and give me some hints on how to fix it? Or if it is right can you confirm? Thanks a lot for the help :)
 

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4 forces really act in the car. Ff, Fc, P, N.
If we have N=0, we have Ff=0
N=PcosI - FcsenI
P=Fc tanI
so mg = mV²/R tanI
tanI = gR/V²

500ft = 152,4m
60mph = 26,8224 m / s

I>60º
 
I'm sorry you lost me. I have never seen that notation. I know N is normal force. Is Ff forward force? P parallel? And I don't know what Fc is. Why would normal force=0? Sorry I am not following.
 
kkk
That answer I've written in brazilian notation, I'm sorry.
I'm going to translate
Ff would go for friction force, that in BR is Força de atrito
Fc would go for centripetal force that in brazil is Força centrípeta
P would go for weght that in brazil is peso
N is normal

Ff = N.u, if Ff = 0, N is null


John
 
So could you tell me what I did wrong, like at which step I made my first error?
 
The centripetal acceleration is horizontal, not parallel to the ramp, because it points towards the center of the circle that the car traces out.
 
So that means my force diagram is incorrect?
 
The forces you drew were okay, but when you applied F=ma, the resulting equations were wrong because the centripetal acceleration has components in both the x and y directions for your choice of axes.
 
Ok thanks guys I'll work on the problem when I get home and I'll let you know if I have any more problems. Thanks again.
 
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