roam
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Homework Statement
A uniform rod of length 0.750 m and mass 1.20 kg is pivoted at one end by a smooth pin as shown below. The rod is released from the vertical position and given a slight nudge to release it from the vertical position of unstable equilibrium.
[PLAIN]http://img175.imageshack.us/img175/9820/angacc40pc.png
When the rod is horizontal:
(a) Calculate its angular acceleration.
(b) Calculate the x and the y components of the acceleration of the centre of mass.
The Attempt at a Solution
First I focus on part (a). I have already obtained the angular velocity:
The potential energy of the system relative to the reference configuration is MgL/2 because the center of mass of the rod is at a height L/2 away from its position in the reference configuration. Conservation of mechanical energy for the system is:
Ki+Ui = Kf + Uf
0+½MgL=½Iω²+0
\omega = \sqrt{\frac{MgL}{\frac{1}{3}ML^2}} = \sqrt{\frac{3g}{L}}
using the given values I get ω=6.26 rad/s, which is the correct velocity.
Now I want to use the equation \alpha = \frac{\Delta \omega}{t} to find the angular acceleration. Here's where I'm stuck. Could anyone please show me how to find the time for this equation?
Correct answer to part (a) is 19.62 rad/s² and for part (b) it is -14.7 m/s²(x-component) and -7.36 m/s² (y-component)
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