Finding Arc Length of c between (2,1,0) and (4,4,log2)

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SUMMARY

The arc length of the path defined by c(t) = (2t, t², log(t)) between the points (2, 1, 0) and (4, 4, log(2)) can be calculated using the appropriate limits of integration derived from the parameter t. The lower limit corresponds to t = 1, where c(1) = (2, 1, 0), and the upper limit corresponds to t = 2, where c(2) = (4, 4, log(2)). The formula for arc length involves integrating the square root of the sum of the squares of the derivatives of the components of c(t).

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  • Familiarity with the Pythagorean theorem in three dimensions
  • Basic logarithmic functions and properties
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Homework Statement




Let c be the path c(t)=(2t,t^2,logt), defined for t>0. Find the arc length of c between the points (2,1,0) and (4,4,log2)

I just have a problem with the limits for the integral...what limits so I set for it after finding the derivative and using Pythagorean theorem...thanks.
 
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Let's start with the beginning, what's the formula for calculating the arc length??
 
If your only problem is limits of integration, you want (2t, t^2,ln(t))= (2, 1, 0) for the lower limit, (2t, t^2, ln(t))= (4, 4, ln(2)). Can you solve 2t= 2 and 2t= 4? (Because those points on the curve, those values of t must satisfy t^2= 1, ln(t)= 0 and t^2= 4, ln(t)= 1, respectively.
 

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