"Find the area of the region described: The region that is enclosed by the rose r=4cos3[theta]"
A= [integral] (1/2)r^2 d[theta]
The Attempt at a Solution
I'll use Q as [theta]..
I'm not really sure, but I set up (1/2) [integral] (16(cos^2)3Q) dQ
.. then I thought we were supposed to use the identity (cos^2)Q = (1/2)(1+cos2Q), but every time I substitute this in and integrate, I get 8[pi] instead of 4[pi], the correct answer. What am I doing wrong?
Thank you so much :]