Finding beta for the boltzman distribution.

[center o bass]

Hello! I'm trying to do a satisfactory derivation of the Boltzmann distribution. By using lagrange multipliers I've come as far as to prove that

P(i) = \frac{1}{Z} e^{-\beta E(i)}
where
Z = \sum_i e^{-\beta E(i)},

but how does one actually establish that
\beta = 1/kT?

 

[vanhees71]

Take a monatomic ideal gas and derive the mean energy,

U=-\frac{\partial \ln Z}{\partial \beta}

and compare with the definition of the temperature,

U=\frac{3}{2} N k T.

 

[Shunyata]

I think that Leonard Susskind does this derivation in one of his lectures on statistical mechanics that is available on youtube.

http://www.youtube.com/watch?v=H1Zbp6__uNw"

 

[center o bass]

Take a monatomic ideal gas and derive the mean energy

Ah, yes that is certainly a way to go. But how could that result possibly be general? Doesn't the distribution apply to any combination of systems who shares a total energy E and a number of particles N?