Finding bounds on triple integral?

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SUMMARY

The discussion focuses on calculating the bounds for a triple integral over a solid defined by an ice-cream cone in the first octant, constrained by the planes x=0 and contained within a sphere of radius 20. The transformation equations provided are x=psin(phi)cos(theta), y=psin(phi)sin(theta), and z=pcos(phi), with the relationship p^2=x^2+y^2+z^2. Participants are guided to consider horizontal slices of thickness dz to determine the appropriate bounds for x, y, and z.

PREREQUISITES
  • Understanding of triple integrals and their applications
  • Familiarity with spherical coordinates and transformations
  • Knowledge of geometric shapes, specifically cones and spheres
  • Basic calculus concepts related to integration
NEXT STEPS
  • Study the derivation of bounds for triple integrals in spherical coordinates
  • Learn about the geometric interpretation of integration over solids
  • Explore examples of integrating functions over conical regions
  • Review the application of horizontal slices in volume calculations
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Students studying calculus, particularly those focusing on multivariable integration, as well as educators looking for examples of integrating over complex geometric shapes.

beallio
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Homework Statement



Integrate the function over the solid given by the "slice" of an ice-cream cone in the first octant bounded by the planes x=0 and and contained in a sphere centered at the origin with radius 20 and a cone opening upwards from the origin with top radius 16.



Homework Equations



x=psin(phi)cos(theta)
y=psin(phi)sin(theta)
z=pcos(phi)

p^2=x^2+y^2+z^2

The Attempt at a Solution


I don't understand how to get the x y and z bounds from the equations given.
 
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Hi beallio! :smile:

Hint: horizontal slices of thickness dz, again, just like the other problem. :wink:
 

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