Finding Center of Mass for a Lamina in First Quadrant

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SUMMARY

The discussion focuses on finding the center of mass for a lamina defined by the region in the first quadrant bounded by the curves y = sin(x) and y = cos(x) from x = 0 to x = π/4, with a density function δ(x,y) = y. Participants clarify that converting to polar coordinates is unnecessary in this case, as working in Cartesian coordinates simplifies the calculations. One user confirmed their solution using Maple, emphasizing the importance of solving the integrals step by step without unnecessary conversions.

PREREQUISITES
  • Understanding of center of mass calculations
  • Familiarity with Cartesian and polar coordinate systems
  • Knowledge of integral calculus
  • Experience with density functions in physics
NEXT STEPS
  • Study the process of calculating center of mass in Cartesian coordinates
  • Learn about polar coordinates and when to apply them in integration
  • Explore the use of computational tools like Maple for solving integrals
  • Review the properties and applications of density functions in physics
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Students in mechanical engineering, physics enthusiasts, and anyone involved in solving problems related to center of mass and integral calculus.

kieranl
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Homework Statement



A lamina has the shape of the region in the first quadrant that is bounded by the graphs of y = sinx and y= cosx, between x = 0 and x = π/4. Find the centre of mass if the density is δ(x,y) = y.

Homework Equations



I know all the equations for moments and center of mass but I am confused about how to go about this problem. I don't know how to convert this to polar. The question is related to the lecture on polar integrals so I am assuming that's what has to be done?

The Attempt at a Solution

 
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Hi kieranl! :smile:
kieranl said:
A lamina has the shape of the region in the first quadrant that is bounded by the graphs of y = sinx and y= cosx, between x = 0 and x = π/4. Find the centre of mass if the density is δ(x,y) = y.

I know all the equations for moments and center of mass but I am confused about how to go about this problem. I don't know how to convert this to polar. The question is related to the lecture on polar integrals so I am assuming that's what has to be done?

Noooo …

you only convert coordinates if it makes the job easier …

for example, if the density function was δ(r,θ) …

in this case, δ = y (and also sin(rsinθ) is horrible ), so the easiest thing is to stay with the (x,y) coordinates. :wink:
 
Heya Kieranl

This is like your third curtin engineering question you've posted, so i'll assume you're probably doing mechanical engineering?

Alls I got to say is that this one took me like 5 pages of working out. I double checked it with maple so I know its right, but maybe i did it in some really long and complicated way. I didnt convert to polar format, although I wasnt sure if I was supposed to. I was just left with 4 integrals which I had to solve step by step.
 

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